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...convert a certain number to binary in C programming?

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Question by am-am
Submitted on 7/6/2003
Related FAQ: comp.lang.c Answers to Frequently Asked Questions (FAQ List)
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how to convert a certain number to binary in C programming?


Answer by madhavi
Submitted on 8/4/2003
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We can convert a number into binary by dividing it with 2

for eg: 48 is there
48/2=24 and reminder R = 0
24/2=12 and R=0
12/2=6 and R=0
6/2= 3 and R=0
3/2 = 1 and so R= 1

So from this we will take all the reminders and so the binary number for 48 is 10000

 

Answer by Darkman_nofear
Submitted on 10/21/2003
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the concept is right but if you follow the bit weight in the binary system it will be (1,2,4,8,16,32,64,128,256,..etc) so by this mentioned answer is the binary number for 16.
but 48 is 110000

 

Answer by naidu_trk
Submitted on 12/29/2003
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There is no conversion to binary as such in  c programming u need to display it in the binary form .

Here is the short function  to do that
[ recursive implementation ]

void bin(int i){/* start bin */
                                                                                int j=0;
                                                                                if(i!=0){
  j=i;
  bin(i>>1);
  printf(" %d ",j&0x01);
   }
  }  /* end bin */

 

Answer by Rahul B
Submitted on 1/29/2004
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Storing the binary representation of a number in a string, is this what you wist to achieve. Try using sprintf() with format strings.

 

Answer by harish
Submitted on 4/7/2004
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# include <stdio.h>
void bin (int);
int main (void)
{
unsigned int num;

printf ("Enter the no: to be converted into binary\n");
scanf ("%d",&num);
bin (num);
}

void bin (int num)
{
while (num != 0)
{
  printf ("%d",num % 2);
  num = num /2;
}
}

 

Answer by idiot_123
Submitted on 10/3/2004
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#include <stdio.h>
#include <conio.h>
#include <conio.c>

int main()
{
    int input, bin_no[8]={0,0,0,0,0,0,0,0},i=7;
    
    
    //do decimal to binary conversion
    
    for(input=0; input<256; input++)
    {
        do
        {
            bin_no[i] = input % 2;
            input = input / 2;
            i--;
         }while(input!=0);
    
        for(i=0 ; i<8 ; i++)
        {      
            printf("%d", bin_no[i]);
        }

        textcolor(WHITE);
        printf("\n");
    }
    system("pause");
    return 0;
}

 

Answer by idiot_123
Submitted on 10/3/2004
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#include <stdio.h>
#include <conio.h>
#include <conio.c>

int main()
{
    int input, bin_no[8]={0,0,0,0,0,0,0,0},i=7;
    
    
    //do decimal to binary conversion
    
    for(input=0; input<256; input++)
    {
        do
        {
            bin_no[i] = input % 2;
            input = input / 2;
            i--;
         }while(input!=0);
    
        for(i=0 ; i<8 ; i++)
        {      
            printf("%d", bin_no[i]);
        }

        textcolor(WHITE);
        printf("\n");
    }
    system("pause");
    return 0;
}

 

Answer by Jignesh makawana
Submitted on 2/26/2005
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We can convert a number into binary by dividing it with 2

for eg: 48 is there
48/2=24 and reminder R = 0
24/2=12 and R=0
12/2=6 and R=0
6/2= 3 and R=0
3/2 = 1 and so R= 1

So from this we will take all the reminders and so the binary number for 48 is 110000

 

Answer by Mau'Dib
Submitted on 4/3/2005
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Darkman_nofear s answer is also partially incorrect. "...so by this mentioned
answer is the binary number for 16.
but 48 is 110000."

Actually:
100000 (base 2) == 32 (base 10) //Not 16.  
110000 (base 2) == 48 (base 10) //Correct.

To convert binary to decimal and
vice versa simply use this eg.:
110001 (b2) = ? (b10)

5  4  3  2  1  0  //Add each 2^n.
1  1  0  0  0  1  //Binary num.

 

Answer by Alexander
Submitted on 10/3/2005
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Here is a bloated example.

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main (int argc, char* argv[]) {

   int total, power, result = 0;
   total = atoi (argv[1]);

   power = (int) (log ((double) total) / log (2));

   for (int x = power; x >= 0; x--) {
      result += (int) (pow (10, x) * int (total / pow (2, x)));
      total %= (int) pow (2, x);
   }

   printf ("%d\n", result);

   return 0;
}

 

Answer by mohan,moni_mvj99@yahoo.com
Submitted on 12/15/2005
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#include<stdio.h>


    void main()
    {
   int a[10];
   int n,i,j;
   printf("enter value");
   scanf("%d",&n);
   for(i=0;i<10;i++)
   {
       if(n==1)
       {
      a[i]=1;
      break;
       }
       else
       {
      a[i]=n%2;
      n=n/2;
       }
   }
       for(j=0;j<=i;j++)
       {
      
      printf("%d",a[j]);
       }
}

 

Answer by marizion
Submitted on 2/9/2006
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/* this function takes the number to convert and a string to place the binary representation of that number in.
*/

void binstring(int num,char * output)
{
int count = 0;
int i,e;
char temp[50];

while(num != 0)
{
  if(num % 2 == 0)
  {
   temp[count++] = '0';
  }
  else
  {
   temp[count++] = '1';
  }
  num = num >> 1;
} // you now have the binary number in temp
   // but it is backwards,
   // eg ( "star" backwards is "rats")

for( i = (--count),e = 0; i >= 0; i--,e++)
{
  output[e] = temp[i];
}
output[e] = '\0';
// we have just used to for loop to reverse
// the letters of the string
// eg ("rats" to "star")
}

 

Answer by a123321
Submitted on 2/14/2006
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quote*****************************
the concept is right but if you follow the bit weight in the binary system it will be (1,2,4,8,16,32,64,128,256,..etc) so by this mentioned answer is the binary number for 16.
but 48 is 110000
**************************************

the first answer given is incomplete, since u need to divide until nothing is left.
for eg: 48 is there
48/2=24 and reminder R = 0
24/2=12 and R=0
12/2=6 and R=0
6/2= 3 and R=0
3/2 = 1 and so R= 1
1/2= 0 and so R=1

and the binary is 110000

 

Answer by Arnaud
Submitted on 11/20/2006
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# include <stdio.h>

printb(int num){
     char str[8];
     printf("%s",itoa(num, str, 2));
}

void main(void){
     printb(17);
}

 

Answer by Arnaud
Submitted on 11/20/2006
Rating: Not yet rated Rate this answer: Vote
# include <stdio.h>

printb(int num){
     char str[8];
     printf("%s",itoa(num, str, 2));
}

void main(void){
     printb(17);
}

 

Answer by sart
Submitted on 11/28/2006
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how to convert 137.1 into binary numbers

 

Answer by Thorsten
Submitted on 1/10/2007
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The previous answer gives the Binary output backwards.  Here is a function for converting to Binary properly:
void convertToBinary()
{
   int num;
   int binary = 0;
   int place = 0;
   printf("Converting to Binary\n");
   printf("Enter an integer: ");
   scanf("%d", &num);
   while (num != 0)
   {
      binary = binary + (num%2 * pow(10, place));
      num = num /2;
      place = place + 1;
   }
   printf("The equivalent binary is %d\n", binary);
}

 

Answer by Fil
Submitted on 3/20/2007
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// this will convert IP address, subnet mask
// and network address to a binary form
// so you can check if IP is valid part of
// network
//
// tnx to man above for original code :)

#include <conio.h>
#include <math.h>
#include <pcap.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <winsock.h>
#include <winnt.h>





void bin(int,int,int,int,int);

int bin_pole_ip[32];
int bin_pole_maska[32];
int bin_pole_siet[32];

void main (void) {

//printf ("Enter the no: to be converted into binary\n");
//scanf ("%d",&num);

bin(192,168,50,5,0);
bin(255,255,255,0,1);
bin(192,168,50,0,2);

   printf("\nIP:    ");
   for(int b_t = 0; b_t < 32; b_t++) {
      
      if(b_t%8 == 0) printf(" ");
      printf("%d",bin_pole_ip[b_t]);

   }

   printf("\nMaska: ");
   for(b_t = 0; b_t < 32; b_t++) {

      if(b_t%8 == 0) printf(" ");
      printf("%d",bin_pole_maska[b_t]);

   }
   
   printf("\nSiet:  ");
   for(b_t = 0; b_t < 32; b_t++) {

      if(b_t%8 == 0) printf(" ");
      printf("%d",bin_pole_siet[b_t]);

   }

   printf("\n\n");

}

void bin(int num,int num2,int num3,int num4,int kam) {

   int counter = 7;

   while (num != 0) {
   
      if(kam == 0) bin_pole_ip[counter] = num % 2;
      if(kam == 1) bin_pole_maska[counter] = num % 2;
      if(kam == 2) bin_pole_siet[counter] = num % 2;
      counter--;
      
      num = num /2;
   }

   counter = 15;

   while (num2 != 0) {
   
      if(kam == 0) bin_pole_ip[counter] = num2 % 2;
      if(kam == 1) bin_pole_maska[counter] = num2 % 2;
      if(kam == 2) bin_pole_siet[counter] = num2 % 2;
      counter--;
      
      num2 = num2 /2;
   }

   counter = 23;

   while (num3 != 0) {
   
      if(kam == 0) bin_pole_ip[counter] = num3 % 2;
      if(kam == 1) bin_pole_maska[counter] = num3 % 2;
      if(kam == 2) bin_pole_siet[counter] = num3 % 2;
      counter--;
      
      num3 = num3 /2;
   }

   counter = 31;

   while (num4 != 0) {
   
      if(kam == 0) bin_pole_ip[counter] = num4 % 2;
      if(kam == 1) bin_pole_maska[counter] = num4 % 2;
      if(kam == 2) bin_pole_siet[counter] = num4 % 2;
      counter--;
      
      num4 = num4 /2;
   }

   


   printf("\n");

}

 

Answer by Gianpa
Submitted on 4/28/2007
Rating: Not yet rated Rate this answer: Vote
#include <stdio.h>

int main() {

int number;
printf("Enter a number to be converted into binary form: ");
scanf("%d",&number);

printf("\nThe converted number is: ");
while (number) {
printf("%d",number%2);
number /= 2;
}

 

Answer by okumbi
Submitted on 4/28/2007
Rating: Not yet rated Rate this answer: Vote
how to conver the binary to get ip/tcp address

 

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