Hello is there any way to make a printf/cout updating??I...

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Answer by Adrian
Submitted on 7/6/2004
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Replace << endl; by << " \r" << flush; endl prints a newline character so that the next line of output appears on the following line of the screen. "\r" is a carriage return, which does not start a new line but simply returns to the beginning of the current line. flush assures that the printed line is actually displayed on the screen (endl has this already built in). There is an additional space character in order to overwrite trailing zeroes when your numbers decrease and have less decimal places. Or you may want to use << setw(2) << i (or whatever width you like) in order to print the value of i right-justified (include <iomanip> for that). In C, you could use printf("...\r"); fflush(stdout); Flushing the output to the screen is needed here, too. Keep in mind that it might depend on your type of terminal whether this code will work as expected or not.

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Question by dager
Submitted on 4/21/2004
Related FAQ: comp.lang.c Answers to Frequently Asked Questions (FAQ List)
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Hello is there any way to make a printf/cout updating??I mean with for(i=10;i<0;i--) cout<<"number = "<<i<<endl; having only one line with `i` changing like a countdown instead of ten lines? thanks a lot

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