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Relativity and FTL Travel
by Jason W. Hinson (hinson@physicsguy.com)
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Part I: Special Relativity
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Edition: 5.1
Last Modified: April 8, 2003
URL: http://www.physicsguy.com/ftl/
FTP (text version): ftp://ftp.cc.umanitoba.ca/startrek/relativity/
This is Part I of the "Relativity and FTL Travel" FAQ. It contains
basic information about the theory of special relativity. In the FTL
discussion (Part IV of this FAQ), it is assumed that the reader understands
the concepts discussed below, while it is not assumed that the reader has
read Parts II and IV of this FAQ as they are "optional reading". Therefore,
if the reader is unfamiliar with special relativity in general (and
especially if the reader is unfamiliar with space-time diagrams) then he or
she should read this part of the FAQ to understand the FTL discussion in
Part IV.
For more information about this FAQ (including copyright information
and a table of contents for all parts of the FAQ), see the Introduction to
the FAQ portion which should be distributed with this document.
Contents of Part I:
Chapter 1: An Introduction to Special Relativity
1.1 Relativity Terminology
1.2 Reasoning for its Existence
1.3 Time Dilation and Length Contraction Effects
1.4 Introducing Gamma
1.5 Energy and Momentum Considerations
1.5.1 Rest Mass versus "Observed Mass"
1.5.2 The Energy and Momentum of a Photon (Where m = 0)
1.6 Experimental Support for the Theory
Chapter 2: Space-Time Diagrams
2.1 What are Space-Time Diagrams?
2.2 Time as Another Dimension
2.3 Basic Information About the Diagrams we will Construct
2.4 Constructing One for a "Stationary" Observer
2.5 Constructing One for a "Moving" Observer
2.6 A Quick Comparison of the two Observers
2.7 Interchanging "Stationary" and "Moving"
2.8 "Future", "Past", and the Light Cone
Chapter 1: An Introduction to Special Relativity
The main goal of this introduction is to make relativity and its
consequences feasible to those who have not seen them before. It should also
reinforce such ideas for those who are already somewhat familiar with them.
This introduction will not really follow the traditional way in which
relativity came about, but it will try to explain the concepts through an
easy to follow perspective. After discussing the basic terminology, the
introduction will discuss points in the pre-Einstein view of relativity. It
will then give some reasoning for why Einstein's view is plausible. This
will lead to a discussion of some of the consequences this theory has, odd
as they may seem. Finally, I want to mention some experimental evidence that
supports the theory.
1.1 Relativity Terminology
As we begin our discussion, I want to first introduce the reader to
some terms which will be used. The first term to consider is the obvious
one, "relativity". Why is this field of study called relativity? Well, it
involves considering how an event or series of events would look to one
observer given that you know how it looks to another observer who may be
moving with respect to the first. This is called "transforming" the
observation from one frame to another, and relativity tells us how to do
that. Thus, we are concerned with the way something seems to one observer
RELATIVE TO how it seems to another. Certain measurements or calculations
will be the same regardless of your frame of reference. They are "frame
independent" or "absolute" or "invariant" in nature. Other aspects of our
universe depend greatly on your frame of reference, and they are thus "frame
dependent" or "relative" in their nature. Relativity is thus study of the
relative nature of things in our universe.
In that last paragraph, I use the term "frame of reference," and I
should take a moment to explain what it is I am talking about. By "frame of
reference" I sort of mean the "point of view" of a particular observer.
Essentially, your frame of reference is what decides your relative "view" of
things, so observers in different reference frames will have different
relative "views". In special relativity, moving with respect to another
observer is what makes your frame of reference different from his. Note too
that frames of reference are relative, so that what we are really concerned
with is what one frame of reference is like with respect to another frame of
reference. Thus, we would say that your frame of reference relative to
another frame depends on your velocity in that other frame of reference.
Now it is very easy for a newcomer to relativity to get mislead by this
concept of frame of reference. The sticky phrase in the above explanation is
"relative 'view' of things." You see, whenever I talk about when something
occurs in some frame of reference, I DO NOT necessarily mean what the
observer in that frame would actually see with their eyes. This is because
the observer only sees the event after the light from the event reaches him.
To figure out when the event actually occurred for that observer, one must
account for the "signal delay". For example, an observer may see an event
today, but if the event occurred on some star ten light-years away (the
distance light would travel in 10 years) in this observer's frame, then we
must realize that the event actually occurred ten years ago in this
observer's frame of reference (because then light from the event would just
be reaching the observer today). I mention this because it is sometimes
tempting for newcomers of relativity to conclude that its odd effects (like
time dilation--which we will discuss later in this chapter) are only
illusions created by the fact that light from an event may reach one
observer before it reaches another. However, here I am clearly stating that
when we talk about when an event occurs in a frame of reference, we are
talking about when it ACTUALLY OCCURRED in that frame after all light signal
delays are taken into account.
Similarly, if I say that event A and event B occur simultaneously in
some frame of reference, I do not mean that an observer in that frame would
necessarily see them occur at the same time, but rather that they actually
happened at the same time. For example, if two explosions really happened at
the same time in our frame of reference, and one occurred on the moon while
the other occurred on the sun, then we would see the one from on the moon
first (because it is closer). However, we must take into account the time it
takes the light to get to us. We must note that it would take longer for the
light from the explosion on the sun to get to us, and we can then understand
why we saw the explosion on the moon first. Then, with the proper
calculations, we could conclude that the explosions actually happened at the
same time in our frame. It will be important to remember that this is what
we mean as we talk about when and where events occur in different frames of
reference (especially in Chapter 2).
Now, with these terms and considerations in mind, we can go on to
reason as to why the theory of relativity exists as it does today.
1.2 Reasoning for its Existence
Before Einstein, there was Newton, and Newtonian physics had its own
concept of relativity; however, it was incomplete. Remember that relativity
involves figuring out what an observation would seem like to one observer
once you knew what it looked like to another observer who is moving with
respect to the first. Before Einstein, this transformation from one frame to
another was not completely correct, but it seemed so in the realm of small
speeds.
Here is an example of the Newtonian idea of transforming from one frame
of reference to another. Consider two observers, you and me, for example.
Let's say I am on a train (in some enclosed, see-through car--if you want to
visualize the situation) that passes you at 30 miles per hour. I throw a
ball in the direction the train is moving such that the ball moves at 10 mph
in MY point of view. Now consider a mark on the train tracks which starts
out ahead of the train. As I am holding the ball (before I throw it), you
will see it moving along at the same speed I am moving (the speed of the
train). When I throw the ball, you will see that the ball is able to reach
the mark on the track before I do. So to you, the ball is moving even faster
than I (and the train). Obviously, it seems as if the speed of the ball with
respect to you is just the speed of the ball with respect to me plus the
speed of me with respect to you. So, the speed of the ball with respect to
you = 10 mph + 30 mph = 40 mph.
This was the first, simple idea for transforming velocities from one
frame of reference to another. It tries to explain a bit about observations
of one observer relative to another observer's observations. In other words,
this was part of the first concept of relativity, but it is incomplete.
Now I introduce you to an important postulate that leads to the concept
of relativity that we have today. I believe it will seem quite reasonable. I
state it as it appears in a physics text by Serway: "the laws of physics are
the same in every inertial frame of reference." (Note that by "inertial
frame of reference" we basically mean a frame of reference which is not
accelerating.) What the postulate means is that if two observers are moving
at a constant speed with respect to one another, and one observes any
physical laws for a given situation in their frame of reference, then the
other observer must also agree that those physical laws apply to that
situation.
As an example, consider the conservation of momentum (which I will
briefly explain here). Say that there are two balls coming straight at one
another. They collide and go off in opposite directions. Conservation of
momentum says that if you add up the total momentum (which for small
velocities is given by the mass of the ball times its velocity) of both the
balls before the collision and after the collision, then the two should be
identical. Now, let this experiment be performed on a train where one ball
is moving in the same direction as the train, and the other is moving in the
opposite direction. An outside observer would say that the initial and final
velocities of the balls are one thing, while an observer on the train would
say they were something different. However, BOTH observers must agree that
the total momentum is conserved. One will say that momentum was conserved
because the total momentum before AND after the collision were both some
number, A; while the other will say that momentum was conserved because the
total momentum before AND after were both some other number, B. They will
disagree on what the actual numbers are, but they will agree that the law
holds. We should be able to apply this postulate to any physical law. If
not, (i.e., if physical laws were different for different frames of
reference) then we could change the laws of physics just by traveling in a
particular reference frame.
A very interesting result occurs when you apply this postulate to the
laws of electrodynamics (the area of physics which deals with electricity
and magnetism). What one finds is that in order for the laws of
electrodynamics to be the same in all inertial reference frames, it must be
true that the speed of electro-magnetic waves (such as light) is the same
for all inertial observers. Perhaps the easiest way to explain why this is
so is to discuss two constants used in basic electrodynamics. They are
denoted as epsilon_0 and mu_0. Epsilon_0 is used in the basic equation which
describes the attraction or repulsion between two electrically charged
particles while mu_0 is used in the basic equation which describes the
magnetic force on a charged particle. According to electrodynamics, these
two constants are properties of the universe, and if any observer in any
frame of reference does an electro-magnetic experiment to measure those
constants, he or she must always come up with the same answers. However, it
is also a property of electrodynamics that the speed (c) of an
electro-magnetic wave (such as light) can be expressed in terms of those two
constants: c = 1/sqrt(mu_0*epsilon_0). If epsilon_0 and mu_0 are constants
for all inertial observers, then so is c.
Thus, requiring the laws of electrodynamics to be the same for all
inertial observers suggests that the speed of light should be the same for
all inertial observers. Simply stating that may not make you think that
there is anything that interesting about it, but it has amazing and
far-reaching consequences. Consider letting a beam of light take the place
of the ball in our earlier example (the one where I was on a train throwing
a ball, and you were outside the train). If the train is moving at half the
velocity of light (c), and I say that the light beam is traveling at the
speed c with respect to me, wouldn't you expect the light beam to look as if
it were traveling one and a half that speed with respect to you? Well,
because of the postulate above, this is not the case, and the old ideas of
relativity in Newton's day fail to explain the situation. All observers must
agree that the speed of any light beam is c, regardless of their frame of
reference. Thus, even though I measure the speed of the light beam to be c
with respect to me, and you see me traveling past you and one half that
speed, still, you must also agree that the light is traveling at the speed c
with respect to you. This obviously seems odd at first glance, but time
dilation and length contraction are what account for the peculiarity.
1.3 Time Dilation and Length Contraction Effects
Now, I give an example of how time dilation can help explain a
peculiarity that arises from the above concept. Again we consider a case
where I am on a train and you are outside the train, but let's give the
train a speed of 0.6 c with respect to you. (Note that c is generally used
to denote the speed of light which is 300,000,000 meters per second. We can
also write this as 3E8 m/s where "3E8" means 3 times 10 to the eighth). Now
I (on the train) shine a small burst or pulse of light so that (to me) the
light goes straight up, hits a mirror at the top of the train, and bounces
back to the floor of the train where some instrument detects it. Now, in
your point of view (outside the train), that pulse of light does not travel
straight up and straight down, but makes an up-side-down "V" shape because
of the motion of the train. This is not just some "illusion", but rather it
is truly the way the light travels RELATIVE TO YOU, and thus this is truly
the way the situation must be considered in your frame of reference. Below
is a diagram of what occurs in your frame:
Diagram 1-1
/|\
/ | \
/ | \
light pulse going up->/ | \<-light pulse on return trip
/ | \
/ | \
/ | \
/ | \
---------|---------->train's motion (v = 0.6 c)
Let's say that the trip up takes 10 seconds in your frame of reference.
The distance the train travels during that time is given by its velocity
(0.6 c) multiplied by that time of 10 seconds:
(Eq 1:1)
(0.6 * 3E8 m/s) * 10 s = 18E8 m
The distance that the light pulse travels on the way up (the slanted line to
the left) must be given by its speed with respect to you (which MUST be c
given our previous discussion) multiplied by the time of 10 seconds:
(Eq 1:2)
3E8 m/s * 10s = 30E8 m
Since the left side of the above figure is a right triangle, and we know the
length of its hypotenuse (the path of the light pulse) and one of its sides
(the distance the train traveled), we can now solve for the height of the
train using the Pythagorean theorem. That theorem states that for a right
triangle the length of the hypotenuse squared is equal to the length of one
of the sides squared plus the length of the other side squared. We can thus
write the following:
(Eq 1:3)
Height^2 + (18E8 m)^2 = (30E8 m)^2
so
Height = [(30E8 m)^2 - (18E8 m)^2]^0.5 = 24E8 m
(It is a tall train because we said that it took the light 10 seconds to
reach the top, but this IS just a thought experiment.) Now we consider my
frame of reference (on the train). In my frame, the light is truly traveling
straight up and straight back down to me. This is truly the way the light
travels in my frame of reference, and so that's the way we must analyze the
situation relative to me. Again, according to our previous discussion, the
light MUST travel at 3E8 m/s as measured by me as well. Further the height
of the train doesn't change because relativity doesn't affect lengths
perpendicular to the direction of motion. Therefore, we can calculate how
long it takes for the light to reach the top of the train in my frame of
reference. That is given by the distance (the height of the train) divided
by the speed of the light pulse (c):
(Eq 1:4)
24E8 m / 3E8 (m/s) = 8 seconds,
and there you have it. To you the event takes 10 seconds, while according to
me it must take only 8 seconds. We measure time in different ways.
You see, to you the distance the light travels is longer than the
height of the train (see the diagram). So, the only way I (on the train)
could say that the light traveled the height of the train while you say that
the SAME light travels a longer distance is if we either (1) have different
ideas for the speed of the light because we are in different frames of
reference, or (2) we have different ideas for the time it takes the light to
travel because we are in different frames of reference. Now, in Newton's
days, they would believe that the former were true. The light would be no
different from, say, a ball, and observers in different frames of reference
can observer different speeds for a ball (remember our first "train" example
in this introduction). However, with the principles of Einstein's
relativity, we find that the speed of light is unlike other speeds in that
it must always be the same regardless of your frame of reference. Thus, the
second explanation must be the case, and in your frame of reference, my
clock (on the fast moving train) is going slower than yours.
As I mentioned in the last part of the previous section, length
contraction is another consequence of relativity. Consider the same two
travelers in our previous example, and let each of them hold a meter stick
horizontally (so that the length of the stick is oriented in the direction
of motion of the train). To the outside observer (you), the meter stick of
the traveler on the train (me) will look as if it is shorter than a meter.
One can actually derive this given the time dilation effect (which we have
already derived), but I wont go through that explanation for the sake of
time.
Now, DON'T BE FOOLED! One of the first concepts which can get into the
mind of a newcomer to relativity involves a statement like, "if you are
moving, your clock slows down." However, the question of which clock is
REALLY running slowly (yours or mine) has NO absolute answer! It is
important to remember that all inertial motion is relative. That is, there
is no such thing as absolute inertial motion. You cannot say that it is the
train that is absolutely moving and that you are the one who is actually
sitting still.
Have you ever had the experience of sitting in a car, noticing that you
seemed to be moving backwards, and then realizing that it was the car beside
which was "actually" moving forward. Well, the only reason you say that
"actually" the other car was moving forward is because you are considering
the ground to be stationary, and it was the other car who was moving with
respect to the ground rather than your car. Before you looked at the ground
(or surrounding scenery) you had no way of knowing which of you was "really"
moving. Now, if you did this in space (with space ships instead of cars),
and there were no other objects around to reference to, and neither space
ship was accelerating (they were moving at a constant speed with respect to
one another) then what would be the difference in saying that your space
ship was the one that was moving or saying that it was the other space ship
that was moving? As long as neither of you is undergoing an acceleration
(which would mean you were not in an inertial frame of reference) there is
no absolute answer to the question of which one of you is moving and which
of you is sitting still. You are moving with respect to him, but then again,
he is moving with respect to you. All motion is relative, and all inertial
frames are equivalent.
So what does that mean for us in this "train" example. Well, from my
point of view on the train, I am the one who is sitting still, while you zip
past me at 0.6 c. Since I can apply the concepts of relativity just as you
can (that's the postulate of relativity--all physical laws are the same for
all inertial observers), and in my frame of reference you are the one who is
in motion, that means that I will think that it is YOUR clock that is
running slowly and that YOUR meter sticks are length contracted.
So, there is NO absolute answer to the question of which of our clocks
is REALLY running slower than the other and which of our meter sticks is
REALLY length contracted smaller than the other. The only way to answer this
question is relative to whose frame of reference you are considering. In my
frame of reference your clock is running slower than mine, but in your frame
of reference my clock is running slower than yours. This lends itself over
to what seem to be paradoxes such as "the twin paradox" (doesn't it seem
like a paradox that we each believe that the other person's clock is running
slower than our own?). Understanding these paradoxes can be a key to really
grasping some major concepts of special relativity. The explanation of these
paradoxes will be given for the interested reader in Part II of this FAQ.
1.4 Introducing Gamma
Now, the closer one gets to the speed of light with respect to an
observer, the slower ones clock ticks and the shorter ones meter stick will
be in the frame of reference of that observer. The factor which determines
the amount of length contraction and time dilation is called gamma.
Gamma for an object moving with speed v in your frame of reference is
defined as
(Eq 1:5)
gamma = 1 / (1 - v^2/c^2)^0.5
For our train (for which v = 0.6 c in your frame of reference), gamma is
1.25 in your frame. Lengths will be contracted and time dilated (as seen by
you--the outside observer) by a factor of 1/gamma = 0.8. That is what we
demonstrated in our example by showing that the difference in measured times
was 10 seconds for you (off the train) and 8 seconds for me (on the train)
in your point of view. Gamma is obviously an important number in relativity,
and it will appear as we discuss other consequences of the theory (including
the effects of special relativity on energy and momentum considerations).
1.5 Energy and Momentum Considerations
Another consequence of relativity is a relationship between mass,
energy, and momentum. Note that velocity involves the question of how far
you go and how long it takes. Obviously, if relativity affects the way
observers view lengths and times relative to one another, one could expect
that any Newtonian concepts involving velocity might need to be re-thought.
For example, because of relativity we can no longer simply add velocities to
transform from one frame to another as we did with the ball and the train
earlier. (However, for small velocities like we see every day, the
differences which comes in because of relativity are much to small for us to
notice).
Further, consider momentum (which in Newtonian mechanics is defined as
mass times velocity). With relativity, this value is no longer conserved in
different reference frames when an interaction takes place. The quantity
that is conserved is relativistic momentum which is defined as
(Eq 1:6)
p = gamma * m * v
where gamma is defined in the previous section.
By further considering conservation of momentum and energy as viewed
from two frames of reference, one can find that the following equation must
be true for the total energy of an unbound particle:
(Eq 1:7)
E^2 = p^2 * c^2 + m^2 * c^4
Where E is energy, m is mass, and p is the relativistic momentum as defined
above.
Now, by manipulating the above equations, one can find another way to
express the total energy as
(Eq 1:8)
E = gamma * m * c^2
Notice that even when an object is at rest (gamma = 1) it still has an
energy of
(Eq 1:9)
E = m * c^2
Many of you have seen something like this stated in context with the theory
of relativity ("E equals m c squared"). It says that because of the
relationship between space and time for different observers as discovered by
special relativity, we must conclude that an object possesses an internal
energy contained in its mass--mass itself contains energy, or, to put it
more eloquently, mass is simply a convenient form of energy.
1.5.1 Rest Mass versus "Observed Mass"
It is important to note that the mass, m, in the above equations has a
special definition which we will now discuss (by "mass", we generally mean
the property of an object that indicates (1) how much force is needed to
cause the object to have a certain acceleration and (2) how much
gravitational pull you will feel from that object in Newtonian gravitation).
First, note what happens to the relativistic momentum (Equation 1:6) of an
object as its speed approaches c with respect to some observer. In that
observer's frame of reference, its momentum becomes very large (because
gamma goes to infinity), especially compared to the old definition of
momentum, p = m*v. However, if we define a property called "observed mass"
as being gamma * m, then we see that the momentum can be written as
(Eq 1:10)
p = (observed mass) * v
We see that the momentum can be written exactly as it was in Newtonian
physics, except that it seems the mass of the object as seen by an outside
observer is larger than its "rest mass" (m). Further, if we take the
relativistic equation for the energy of an object, Equation 1:8, we see it
too can be written as
(Eq 1:11)
E = (observed mass) * c^2
This is like the energy of an object at rest (E = m*c^2) with the "observed
mass" substituted in for the "rest mass."
Thus, one way to interpret relativity's effect on our view of momentum
and energy is to say that because of relativity, an observer sees an
object's mass increase as the object approaches the speed of light in that
observer's frame of reference. The mass (m) in our equations is thus the
mass as measured when the object is at rest in our frame of reference (the
rest mass), not the "observed mass" we have defined.
However, this concept of observed mass doesn't really work for
gravitational mass. In a relativistic setting, you can't figure out the
gravitational effects of an object that is moving (in your frame) by simply
figuring out what gravitational effects its mass would have at rest and
replacing its mass with the observed mass in your frame of reference. For
example, as the velocity of an object with respect to you approaches c, its
"observed mass" approaches infinity. However, this does not mean that the
object will eventually look like a black hole predicted by general
relativity (as it would if the same object really did have a huge mass
sitting at rest).
Also, let's look at kinetic energy in relation to mass. Kinetic energy
is energy of motion--it's the total energy of a free object minus the amount
of that energy that is internal to the object:
(Eq 1:12)
E_kinetic = E_total - E_internal
= gamma*m*c^2 - m*c^2
= (gamma-1) *m*c^2
As it turns out, when v is much smaller than c, the equation gamma-1 is
approximately equal to (1/2)*v^2/c^2 such that E_kinetic is approximately
(1/2)*m*v^2 (that's the Newtonian equation for kinetic energy which is
approximately correct for non-relativistic speeds). But with relativistic
velocities, the kinetic energy becomes much larger than we would have
calculated it to be using the Newtonian equations. In that sense, there does
seem to be some "extra energy" which could be considered as extra mass
energy; however, you can't get the correct kinetic energy in relativity by
simply plugging our expression for "observed mass" into the Newtonian
equation for kinetic energy. The observed mass concept doesn't really work
here, and we see that it's better to simply argue that the mass isn't really
increasing, but rather the equations for energy and momentum are different
than expressed by Newtonian physics.
So, "observed mass" has its uses, but physicists today rarely use the
concept in practice. Rather, an object is said to have a rest mass (which
truly is its inherent internal energy) as well as an energy due to its
motion with respect to an observer (kinetic energy) which come together to
produce its total energy, E.
1.5.2 The Energy and Momentum of a Photon (Where m = 0)
We should quickly note the case where the rest mass of an object is
zero (such is the case for a photon--a particle of light). Given the
equation for the energy in the form of Equation 1:8 (E = gamma*m*c^2), one
might at first glance think that the energy was zero when m = 0. However,
note that massless particles like the photon travel at the speed of light.
Since gamma goes to infinity as the velocity of an object goes to c, the
equation E = gamma*m*c^2 involves one part which goes to zero (m) and one
part which goes to infinity (gamma). Thus, it is not obvious what the energy
would be. However, if we use the energy equation in the form of Equation 1:7
(E^2 = p^2*c^2 + m^2*c^4), then we can see that when m = 0 then the energy
is given by E = p*c).
Now, a photon has a momentum (it can "slam" into particles and change
their motion, for example) which is determined by its wavelength (lambda) in
the equation p = h/lambda (where h = 6.626E(-34) Joules is called Planck's
constant). A photon of wavelength lambda thus has an energy given by E = p*c
= h*c/lambda, even though it has no rest mass.
1.6 Experimental Support for the Theory
These amazing consequences of relativity do have experimental
foundations. For example, using atomic clocks and super-sonic jets, we have
been able to confirm the effects of time dilation just as relativity
predicts. Another experimental confirmation involves the creation of
particles called muons by cosmic rays (from the sun) in the upper
atmosphere. These muons then travel at very fast speeds towards the earth.
In the rest frame of a muon, its life time is only about 2.2E-6 seconds.
Even if the muon could travel at the speed of light, it could still go only
about 660 meters during its life time. Because of that, they should not be
able to reach the surface of the Earth. However, it has been observed that
large numbers of them do reach the Earth. From our point of view, time in
the muon's frame of reference is running slowly, since the muons are
traveling very fast with respect to us. So the 2.2E-6 seconds are slowed
down, and the muon has enough time to reach the earth.
We must also be able to explain the result from the muon's frame of
reference. In its point of view, it does have only 2.2E-6 seconds to live.
However, the muon would say that it is the Earth which is speeding toward
the muon. Therefore, the distance from the top of the atmosphere to the
Earth's surface is length contracted. Thus, from the muon's point of view,
it lives a very small amount of time, but it doesn't have that far to go.
This is an interesting point of Relativity--the physical results (e.g. the
muon reaches the Earth's surface) must be true for all observers; however,
the explanation as to how it came about can be different for different
frames of reference.
Another verification of special relativity is found all the time in
particle physics. In particle physics, large accelerators push particles to
speeds very close to the speed of light, and experimenters then cause those
particles to strike other particles. The results of such collisions can be
understood only if one uses the momentum and energy equations which were
predicted by relativity (for example, one must take the total energy of the
particle to be E = gamma*m*c^2, which was predicted by relativity).
These are only a few examples that give credibility to the theory of
relativity. Its predictions have turned out to be true in many cases, and to
date, no evidence exists that would tend to undermine the theory in the
areas where it applies.
In the above discussion of relativity's effects on space and time we
have specifically mentioned length contraction and time dilation. However,
there is a little more to it than that, and the next section attempts to
explain this to some extent.
Chapter 2: Space-Time Diagrams
In this section we examine certain constructions known as space-time
diagrams. After a short look at why we need to discuss these diagrams, I
will explain what they are and what purpose they serve. Next we will
construct a space-time diagram for a particular observer. Then, using the
same techniques, we will construct a second diagram to represent the
coordinate system for a second observer who is moving with respect to the
first observer. This second diagram will show the second observer's frame of
reference with respect to the first observer; however, we will also switch
around the diagram to show what the first observer's frame of reference
looks like with respect to the second observer. Finally, we will compare the
concepts these two observers have of future and past, which will make it
necessary to first discuss a diagram known as a light cone.
2.1 What are Space-Time Diagrams?
In the previous section we talked about the major consequences of
special relativity, but now I want to concentrate more specifically on how
relativity causes a transformation of space and time. Relativity causes a
little more than can be understood by simple notions of length contraction
and time dilation. It actually results in two different observers having two
different space-time coordinate systems. The coordinates transform from one
frame to the other through what is known as a Lorentz Transformation.
Without getting deep into the math, much can be understood about such
transforms by considering space-time diagrams.
2.2 Time as Another Dimension
One of the first points to make as we begin discussing space-time
diagrams is that we are treating time as another dimension along with the
three dimensions of space. Generally, people aren't used to thinking of time
as just another dimension, but doing so allows us to truly understand how
relativity works. So, how do we represent time as just another dimension?
Obviously we can't actually picture four dimensions all at once (three
of space and one of time). Our minds are limited to picturing the three
dimensions of space that we are used to dealing with. However, we can
consider one or two dimensions of space and then use another dimension of
space to represent time.
To see how this can work, consider Diagram 2-1. There you see a film
strip on which each frame represents a moment in time. As you watch a film,
you see each moment in time presented one right after another, and this
gives the impression of seeing time pass. If we cut the film up into frames
then we can stack the frames flat, evenly spaced, and one on top of the
other (as shown in the diagram). Then each frame is a two dimensional
representation of space and as you move through the third dimension you go
up the stack, and each frame you pass represents another point in time.
Thus, we have a three dimensional stack which represents two dimensions of
space and the third dimension represents time.
Diagram 2-1
|o|---------|o|
|o|* |o| ___________
|o| |o| ^ /* /
|o| |o| 5 | / /
|o| |o| | / / 5
|o| |o| | / /
|o|---------|o| | /__________/
|o| |o| | ___________
|o| * |o| | / /
|o| |o| 4 | / * /
|o| |o| T | / / 4
|o| |o| | / /
|o|---------|o| I | /__________/
|o| |o| | ___________
|o| |o| M | / /
|o| * |o| 3 | / /
|o| |o| E | / * / 3
|o| |o| | / /
|o|---------|o| | /__________/
|o| |o| | ___________
|o| |o| | / /
|o| |o| 2 | / /
|o| * |o| | / / 2
|o| |o| | / * /
|o|---------|o| | /__________/
|o| |o| | ___________
|o| |o| | / /
|o| |o| 1 | / /
|o| |o| | / / 1
|o| *|o| | / /
|o|---------|o| /_________*/
Film
Note too that in the diagram the film shows a ball moving from one
corner of the screen to the other. However, in the three dimensional stack,
the ball now follows a three dimensional path through space-time. In four
dimensional space-time, objects which we see moving in time through three
dimensional space are following a four-dimensional path through space-time.
On space-time diagrams, paths you draw represent objects moving through
space as time passes, but we'll see more about that later in the chapter.
Further, consider an event such as "the ball reaches the far corner of
the screen." That is a single event--it occurs at one moment in time and at
one particular place in space. On our diagram, it is a single point (it is a
spot represented by the ball which is on the upper most frame in the stack).
Any single event which occurs is represented by a single point on a
space-time diagram.
And so, a space-time diagram gives us a means of representing events
which occur at different locations and at different times. Every event is
portrayed as a point somewhere on the space-time diagram.
Now, because of relativity, different observers which are moving
relative to one another will have different coordinates for any given event.
However, with space-time diagrams, we can picture these different coordinate
systems on the same diagram, and this allows us to understand how they are
related to one another.
2.3 Basic Information About the Diagrams we will Construct
In Diagram 2-1 we saw how one can use three dimensions to represent two
dimensions of space and one of time, but for simplicity the diagrams we use
will be two dimensional--one of space and one of time. We will consider the
one dimension of space to be the x direction. So, the space-time diagram
consists of a coordinate system with one axis to represent space (the x
direction) and another to represent time. Where these two principal axes
meet is the origin. This is simply a point in space that we have defined as
x = 0 and a moment in time that we have defined as t = 0. In Diagram 2-2
(below) I have drawn these two axes and marked the origin with an o.
For certain reasons we want to define the units that we will use for
distances and times in a very specific way. Let's define the unit for time
to be the second. This means that moving one unit up the time axis will
represent waiting one second of time. We then want to define the unit for
distance to be a light second (the distance light travels in one second). So
if you move one unit to the right on the x axis, you will be considering a
point in space that is one light second away from your previous location. In
Diagram 2-2, I have marked the locations of the different space and time
units (Note: In my ASCII diagrams, I am using four spaces to represent one
unit along the x axis and two character heights to represent one unit on the
time axis).
With these units, it is interesting to note how a beam of light is
represented in our diagram. Consider a beam of light leaving the origin and
traveling to the right. One second later, it will have traveled one light
second away. Two seconds after it leaves it will have traveled two light
seconds away, and so on. So a beam of light will always make a line at an
angle of 45 degrees to the x and t axes. I have drawn such a light beam in
Diagram 2-3.
Diagram 2-2 Diagram 2-3
t t
^ ^
| | light
+ + /
| | /
+ + /
| | /
-+---+---o---+---+---> x -+---+---o---+---+-> x
| |
+ +
| |
+ +
| |
2.4 Constructing One for a "Stationary" Observer
At this point, we want to decide exactly how to represent events on
this coordinate system for a particular observer. First note that it is
convenient to think of any particular space-time diagram as being
specifically drawn for one particular observer. For Diagram 2-2, that
particular observer (let's call him the O observer) is the one whose
coordinate system has the vertical time axis and horizontal space axis shown
in that diagram. Now, other frames of reference (which don't follow those
axes) can also be represented on this same diagram (as we will see).
However, because we are used to seeing coordinate systems with horizontal
and vertical axes, it is natural to think of this space-time diagram as
being drawn specifically with the O observer in mind. In fact, we could say
that in this space-time diagram, the O observer is considered to be "at
rest".
So if the O observer starts at the origin, then one second later he is
still at x = 0 (because he isn't moving in this coordinate system). Two
seconds later he is still at x = 0, etc. If we look at the diagram, we see
that this means he is always on the time axis in our representation.
Similarly, any lines drawn parallel to the t axis (in this case, vertical
lines) will represent lines of constant position. If a second observer is
not moving with respect to the first, and this second observer starts at a
position two light seconds away to the right of the first, then as time
progresses he will stay on the vertical line that runs through x = 2.
Next we want to figure out how to represent lines of constant time. We
might first find a point on our diagram that represents an event which
occurs at the same time as, say, the origin (t = 0). To do this we will use
a method that Einstein used. First we choose a point on the t axis which
occurred prior to t = 0. Let's use an example where this point occurs at t =
-3 seconds. At that time we send out a beam of light in the positive x
direction. If the beam bounces off of a distant mirror at t = 0 and heads
back toward the t axis, then it will come back to the us at t = 3 seconds.
We know this because (1) it will have traveled for three seconds away from
us, (2) it will have the same distance to travel back to us in our frame of
reference, and (3) according to relativity it must travel at the same speed,
c, going AND coming back. Thus, it must take three seconds to get back to us
as well which means it reaches as at the time t = 3 seconds. So, if we send
out a beam at t = -3 seconds and it returns at t = 3 seconds, then the event
"it bounced off the mirror" occurred simultaneously with the time t = 0 at
the origin.
To use this on our diagram, we first pick the two points on the t axis
that mark t = -3 and t = 3 (let's call these points A and B respectively).
We then draw one light beam leaving from A in the positive x direction. Next
we draw a light beam coming to B in the negative x direction. Where these
two beams meet (let's call this point C) marks the point where the original
beam bounces off the mirror. Thus the event marked by C is simultaneous with
t = 0 (the origin). A line drawn through C and o will thus be a line of
constant time. All lines parallel to this line will also be lines of
constant time. So any two events that lie along one of these lines truly
occur at the same time in this frame of reference. I have drawn this
procedure in Diagram 2-4, and you can see that the x axis is the line
through both o and C which is a line of simultaneity (as one might have
expected).
Note that the event marked by C is not seen by the O observer (who,
remember, is represented by the t axes because he sits at x = 0) at the
moment it happens (t = 0) but it is seen once light from C reaches the O
observer (which is the point marked B). However, because of the way we did
the experiment, we know that in this frame of reference, C truly did happen
simultaneously with the origin, o. This just goes to illustrate, as
discussed in Section 1.1, that when I say that two events happened
simultaneously in some frame of reference, I am not talking about when they
are seen by some observer in that frame. Rather, I am talking about when
they actually occur in that frame of reference. On our diagrams, events are
represented at their actual space-time locations relative to one another,
and in a particular frame of reference that means that we show exactly when
and where the event occurred (not "observed" but truly occurred) in that
frame.
Now, by constructing a set of simultaneous time lines and constant
position lines we will have a grid on our space-time diagram. Any event has
a specific location on the grid which tells where and when it occurs in this
frame of reference. In Diagram 2-5 I have drawn one of these grids and
marked an event (@) that occurred 3 light seconds away to the left of the
origin (x = -3) and 1 second before the origin (t = -1).
Diagram 2-4 Diagram 2-5
t
|
B t
| \ | | | | | |
+ \ ---+---+---+---+---+---+---
| \ | | | | | |
+ \ ---+---+---+---+---+---+---
| \ | | | | | |
-+---+---o---+---+---C- x ---+---+---+---o---+---+--- x
| / | | | | | |
+ / ---@---+---+---+---+---+---
| / | | | | | |
+ / ---+---+---+---+---+---+---
| / | | | | | |
A
|
2.5 Constructing One for a "Moving" Observer
Now comes an important addition to our discussion of space-time
diagrams. The coordinate system we have drawn will work fine for any
observer who is not moving with respect to the O observer. Now we want to
construct a coordinate system for an observer who IS traveling with respect
to the O observer. The trajectories of two such observers have been drawn in
Diagram 2-6 and Diagram 2-7. Notice that in our discussion we will usually
consider moving observers who pass by the O observer at the time t = 0 and
at the position x = 0. Thus, the origin will mark the event "the two
observers pass by one another".
Now, the traveler in Diagram 2-6 is moving slower than the one in
Diagram 2-7. You can see this because in a given amount of time (distance
along the t axis), the Diagram 2-7 traveler has moved further away from the
time axis than the Diagram 2-6 traveler. So the faster a traveler moves, the
more slanted this line becomes.
Diagram 2-6 Diagram 2-7
t t
| / | /
+ + /
| / | /
+ + /
|` |/
-+---+---o---+---+--- x -+---+---o---+---+- x
,| /|
+ / +
/ | / |
+ / +
/ | / |
What does this line actually represent? Well, remember that the line
marks the position of our observer at different times on our diagram. But,
also, consider an object sitting right next to our moving observer. If a few
seconds later the object is still sitting right next to him (practically on
that line), then, in his point of view, the object has not moved. So, the
line is a line of constant position for the moving observer. Nothing on that
line is moving with respect to him. But that means that this line represents
the same thing for the moving observer as the t axis represented for the O
observer; and in fact, this line becomes the moving observer's new time
axis. We will mark this new time axis as t' (t-prime). All lines parallel to
this slanted line will also be lines of constant position for our moving
observer.
Now, just as we did for the O observer, we want to construct lines of
constant time for our traveling observer. To do this, we will use the same
method that we did for the O observer. The moving observer will send out a
light beam at some time t'= -T, and the beam will bounce off some mirror so
that it returns to him at time t'= +T. Now remember, light travels at the
same speed in any direction for ALL observers, so our traveling observer
must conclude that the light beam took the same amount of time traveling out
as it did coming back in his frame of reference. If in his frame the light
left at t'= -T and returned at t'= +T, then the point at which the beam
bounces off the mirror must have occurred simultaneously with the origin,
where t'= t = 0, in the frame of reference of our moving observer.
There is a very important point to note here. What if instead of light,
we wanted to throw a ball at 0.5 c, have it bounce off some wall, and then
return at the same speed (0.5 c). The problem with this is that to find a
line of constant time for the moving observer, the ball must travel at 0.5 c
BOTH WAYS in the reference frame of the MOVING observer. But we have not yet
defined the coordinate system for the moving observer, so we do not know
what a ball moving at 0.5 c with respect to him will look like on our
diagram. However, because of relativity, we know that the speed of light
itself CANNOT change from one observer to the next. In that case, a beam of
light traveling at c in the frame of the moving observer will also be
traveling at c for the O observer. So, a line which makes a 45 degree angle
with respect to the x and t axes will ALWAYS represent a beam of light
traveling at speed c for ANY observer in ANY frame of reference.
In Diagram 2-8, I have labeled a point A' on the t' axes which occurs
some amount of time before t'= 0 and a point B' which occurs the same amount
of time after t'= 0. I then drew the two light rays (remember, these are "45
degree angle" lines) as before--one leaving from A and going to the right,
and one moving to the left and coming in to B. I then found the point where
they would meet (C') which marks the point where the ray from A' would have
had to bounce in order to get back to the moving observer at B'. Thus, C'
and o occur at the same time in the frame of the moving observer. Notice
that for the O observer, C' is above his line of simultaneity at o (the x
axis). So while the moving O' observer says that C' occurs when the two
observers pass (at the origin), the O observer says that C' occurs after the
two observers have passed by one another. We will further discuss this
difference in the concepts of future and past in Section 2.8.
In Diagram 2-9, I have drawn a line passing through C' and o. This line
represents the same thing for our moving observer as the x axis did for the
O observer. So we label this line x'.
Diagram 2-8 Diagram 2-9
t t t'
| / | /
+ B' + /
| / \ | / __--x'
+ / C' + / __C'-
|/ / |/__--
-+---+---+---o---/---+---+- x -+---+---+-__o---+---+---+- x
/| / * __-- /|
/ / __-- / +
// | -- / |
A' + / +
/ | / |
From the geometry involved in finding this x' axis, we can state a
general rule for finding the x' axis for any moving observer. First recall
that the t' axis is the line that represents the moving observer's position
on the space-time diagram. The faster O' is moving with respect to O, the
greater the angle between the t axis and the t' axis. So the t' axis is
rotated away from the t axis at some angle (either clockwise or
counterclockwise, depending on the direction O' is going--right or left).
The x' axis is then a line rotated at the same angle away from the x axis,
but in the opposite direction (counterclockwise or clockwise).
Now, x' is a line of constant time for O', and any line drawn parallel
to x' is also a line of constant time. Such lines, along with the lines of
constant position, form a grid of the space-time coordinates for the O'
observer. I have tried my best to draw such a grid in Diagram 2-10. If you
squint your eyes while looking at that diagram, you can see the skewed
squares of the coordinate grid. You can see that if you pick a point on the
space-time diagram, the two observers with their two different coordinate
systems will disagree on when and where the event occurs.
Diagram 2-10
t'
+-----------------/-------+
| / /_-/""/ /__/-"/ / _|
|/-"/ / _/--/" / /_-/""/|
| /_-/""/ /__/-"/ / _/-->x'
|"/ / _/--/" / /_-/""/ |
|/_-/""/ /__o-"/ / _/--/|
| / _/--/" / /_-/""/ /_|
|-/""/ /__/-"/ / _/--/" |
|/ _/--/" / /_-/""/ /__/|
|""/ /__/-"/ / _/--/" / |
+-------------------------+
As a final note about this procedure, think back to what really made
these two coordinate systems look differently. Well, the only thing we
assumed in creating these systems is that the speed of light is the same for
all observers. In fact, this is the only reason that the two coordinate
systems look the way they do.
2.6 A Quick Comparison of the two Observers
For a moment, I want to go back and compare the two observers in
Diagram 2-8. Consider how the O observer would explain the experiment done
by the O' observer. First note that in the coordinate system used by the O
observer, the point marked C' is above the x axis. This means that in the O
observer's frame of reference, C' happens after the origin (when the two
observers pass by one another). However, we concluded that for O' the C'
event happens at the same time as the two observers are passing one another.
What does that mean?
Look at the parts of the experiment O' did (including the actions of O'
and the events A', B', and C') as they appear in the O observer's frame. In
that frame, O' sends out a light signal when his own clock reads t' = -T,
but note also that he is moving along with that signal (according to O). The
distance between them changes slowly at the beginning according to O because
O' is moving along with the signal in the same direction. Then, according to
O, the two observers pass by one another. Next, the C' event happens and the
light bounces back toward the two observers. In the frame of the O observer,
the O' observer is now racing towards the light beam, and so the distance
between them is changing very quickly. Finally, the light beam reaches O' as
his clock is ticking t' = +T.
So, we see that in the O frame of reference, because O' is moving along
with the light before C' and is moving towards the light after C' that means
C' has to happen after the "half way point" (when the two observers pass one
another).
HOWEVER, relativity says that O' cannot agree with that analysis. In
the frame of O', it is the O observer who is moving. Further, O' cannot
agree that the distance between him and the light is changing slowly before
C' and quickly after C'. Why can't he agree? Well, because then he would
measure the speed of the light in his frame of reference and find it to be
different going away from him than it is coming back to him. As discussed in
Section 1.2, relativity dictates that for ANY inertial observer, when he
measures the speed of light he MUST find the speed to be c--ALWAYS, and in
ALL directions. If O' has to find that the light is traveling at the same
speed going and coming back, then O' also has to conclude that in his frame
C' really, truly happens at the same time as the origin (when and where the
two observers pass one another). O' thus has a different coordinate system
than O, and he measure space and time differently.
And so, in one frame of reference C' really, truly happens after the
two observers pass one another, but in another frame of reference C' really,
truly happens and the same time the two observer's pass. We find that the
notion of simultaneity is relative, and we will discuss this further in just
a bit.
Next, though, I want to address a possibility you might be thinking
right now. That is, why can't it simply be that O' is just wrong in
interpreting things as he does and that O is correct. One might want to
claim that the reason O' is confused is that he is moving while O is not.
But next we will see that we can interchange the two observers, and it
becomes obvious that there is no absolute way to claim that one of them is
the "correct" observer.
2.7 Interchanging "Stationary" and "Moving"
In our understanding of space-time diagrams, we need to incorporate the
idea that all reference frames that are not accelerating are considered
equivalent and that all motion is relative. By this I mean that O was
considered as the stationary observer only because we defined him as such.
Remember? We said that this it is natural to think of the diagram being
drawn specifically for the observer whose coordinate system is drawn with
vertical and horizontal axes. We then said that we can think of that
observer (O) to be considered "at rest" in this diagram. Then, when I called
O' the moving observer, I meant that he was moving with respect to O.
However, we should just as easily be able to define O' as the
stationary observer. Then, to him, O is moving away from him to the left.
Then, we should be able to draw the t' and x' axes as the vertical and
horizontal lines, while the t and x axes become the rotated lines. I have
done this in Diagram 2-11. By examining this diagram, you can confirm that
it makes sense to you in light of our discussion thus far. (For example,
picture grabbing the x' and t' axes in Diagram 2-9 and rotating them around
the origin until they are horizontal and vertical lines. If x and t follow
your rotation, then you can see how they would end up as they are drawn in
Diagram 2-11.)
Diagram 2-11
t'
|
t B'
\ | \
\ + \
\ | \
\ + \
\| \
---+---+---o---+---+---C'- x'
| ""__ /
+ ""--
| / ""_C
+ / ""--x
| /
A'
|
I have also included in Diagram 2-11 the experiment that O' did in
which he decided how to draw the x' axis, and you can see that it now looks
just like the experiment O did when his x and t axes were the horizontal and
vertical lines. Further in Diagram 2-11 you can see that the experiment done
by the O observer now looks like the one which has incorrectly concluded
that C occurs at the same time the two observers are passing one another.
Thus, you can see that we can completely interchange the concept of
which observer is moving and which is sitting still, and as a result we must
conclude that neither frame of reference is any "better" than the other.
When O concludes that C occurs simultaneous with o, he is REALLY, TRULY
correct for his frame of reference. Also, when O' concludes that it is C'
which occurs simultaneous with o, he is also REALLY, TRULY correct for his
frame of reference. The notion of simultaneity is not absolute, but REALLY,
TRULY depends on your frame of reference. To understand why this doesn't
cause contradictions, we go to the next section in which we discuss the
notion of future and past with relativity in mind.
2.8 "Future", "Past", and the Light Cone
For the later FTL discussions, it will be important to understand the
way different observers have different notions concerning the future and the
past. This difference comes about because of the way the different
coordinate systems of the two observers compare to one another.
First, let me note that with what we have discussed we cannot make a
complete comparison of the two observers' coordinate systems. You see, we
have not seen how the lengths which represents one unit of space and time in
the reference frame of O compare with the lengths representing the same
units in O'. This will be covered in the Part II: More on Special Relativity
(which is "optional" for those of you just interested in the faster than
light discussions). We can, however, compare the observers' notions of
future and past.
Back on Diagram 2-9, in addition to the O and O' space and time axes, I
also marked a particular event with a star, "*". Recall that for O, any
event on the x axis occurs at the same time as the origin (the place and
time that the two observers pass each other). Since the marked event appears
under the x axis, then O must find that the event occurs before the
observers pass each other in his frame. Also recall that for O', those
events on the x' axis are the ones that occur at the same time the observers
are passing. Since the marked event appears above the x' axis, O' must find
that the event occurs after the observers pass each other in his frame. So,
when and where events occur with respect to other events is completely
dependent on ones frame of reference. Note that this is not a question of
when the events are seen to happen in different frames of reference, but it
is a question of when they really do happen in the different frames (recall
our discussion of reference frames in Section 1.1). So, how can this make
sense? How can one event be both in the future for one observer and in the
past for another observer. To better understand why this situation doesn't
contradict itself, we need to look at one other construction typically shown
on a space-time diagram.
In Diagram 2-12 I have drawn two light rays, one which travels in the
+x direction and another which travels in the -x direction. At some negative
time, the two rays were headed towards x = 0. At t = 0, the two rays finally
get to x = 0 and cross paths (at the origin). As time progresses, the two
then speed away from x = 0. This construction is known as a light cone.
Diagram 2-12
t
^
| light
\ + /
\ inside /
\ + /
outside \ | / outside
---+---+---o---+---+---> x
/ | \
/ + \
/ inside \
/ + \
|
A light cone divides a space-time diagram into two major sections: the
area inside the cone and the area outside the cone (as shown in Diagram 2-12
). (Let me mention here that I will specifically call the cone I have drawn
"a light cone centered at the origin", because that is where the two beams
meet.) Now, consider an observer who has been sitting at x = 0 (like our O
observer) and is receiving and sending signals at the moment marked by x =
0, t = 0 (at the origin). Obviously, if he sends out a signal, it proceeds
away from x = 0 into the future, and the event marked by someone receiving
the signal would be above the x axis (in his future). Also, if he is
receiving signals at t = 0 , then the event marked by someone sending the
signal would have to be under the x axis (in his past). Now, if it is
impossible for anything to travel faster than light, then the only events
occurring before t = 0 that the observer can know about at the moment are
those that are inside the light cone. Also, the only future events (those
occurring after t = 0) that he can influence are, again, those inside the
light cone.
Now, one of the most important things to note about a light cone is
that its position is the same for all observers (because the speed of light
is the same for all observers). For example, picture taking the skewed
coordinate system of the moving observer and superimposing it on the light
cone I have drawn (note: a diagram which shows this view will be given in
Part II: More on Special Relativity). If you were to move one unit "down"
the x' axis (a distance that represents one light second for our moving
observer), and you move one unit "up" the t' axes (one second for our moving
observer), then the point you end up at should lie somewhere on the light
cone. In effect, a light cone will always look the same on our diagram
regardless of which observer is drawing the cone.
This fact has great importance. Consider different observers who are
all passing by one another at some point in space and time. In general, they
will disagree with each other on when and where different events had and
will occur. However, if you draw a light cone centered at the point where
they are passing each other, then they will ALL agree as to which events are
inside the light cone and which events are outside the light cone. So,
regardless of the coordinate system for any of these observers, the
following facts remain: The only events that any of these observers can ever
hope to influence are those which lie inside the upper half of the light
cone. Similarly, the only events that any of these observers can know about
as they pass by one another are those which lie inside the lower half of the
cone. Since the light cone is the same for all the observers, then they all
agree as to which events can be known about as they are passing and which
can be influenced at some point after they pass.
Now let's apply this to the observers and event in Diagram 2-9. As you
can see, the marked event is indeed outside the light cone. Because of this,
even though the event is in one observer's past at the time in question (t =
t'= 0), he cannot know about the event at the time. Also, even though the
event is in the other observer's future at the time, he can never have an
effect on the event after. In essence, the event (when it happens, where it
happens, how it happens, etc.) is of absolutely no consequence for these two
observers at the time in question. As it turns out, anytime you find two
observers who are passing by one another and an event which one observer's
coordinate system places in the past and the other observer's coordinate
system places in the future, then the event will always be outside of the
light cone centered at the point where the observers pass.
But doesn't this relativistic picture of the universe still present an
ambiguity in the concepts of past and future? Perhaps philosophically it
does, but not physically. You see, the only time you can see these
ambiguities is when you are looking at the whole space-time picture at once.
If you were one of the observers who is actually viewing space and time,
then as the other observer passes by you, your whole picture of space and
time can only be constructed from events that are inside the lower half of
the light cone. If you wait for a while, then eventually you can get all of
the information from all of the events that were happening around the time
you were passing the other observer. From this information, you can draw the
whole space-time diagram, and then you can see the ambiguity. But by that
time, the ambiguity that you are considering no longer exists. So the
ambiguity can never actually play a part in any physical situation. Finally,
remember that this is only true if nothing can travel faster than the speed
of light.
Well, that concludes our introduction to special relativity and
space-time diagrams. The next section deals with these concepts with more
detail; however, if the reader wishes to skip to the FTL discussion, the
information provided in the above sections should be enough to follow that
discussion.
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Relativity and FTL Travel--PART I (suggested reading)
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Relativity and FTL Travel--PART I (suggested reading)
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