Top Document: Invariant Galilean Transformations On All Laws Previous Document: 8. What does sci.math have to say about x0'=x0-vt? Next Document: 10. But Isn't (x'-x.c')=(x-x.c) Actually Two Transformations? See reader questions & answers on this topic! - Help others by sharing your knowledge That idea is one of the most idiotic to come up, and it does so frequently. And in a number of guises. The idea being that x.c' <> x.c-vt, with x.c being what we have called x0 above; the notation makes no difference. Some crackpots have managed to maintain that position even after graphs have illustrated that such an idea means that after a while a circle center represented by x.c' could be outside the circle. The leading crackpot just make that explicit, as far as one can tell from his befuddled post in response to a line about "active" transforms, which are actually moving body situations, not coordinate transformations: -------------------------------------------------------------------- e>An active transform is not a coordinate transform, ... Right, it is a transform of the center (in the opposite direction) done to effect the change of coordinates without a coordinate transform. ... E: Transform of the center? Center of a circle? He really is saying a circle center moves in the opposite direction of the circle! Right? -------------------------------------------------------------------- If r=10 and x.c was at x.c=0, then the points on the circle (10,0), (-10,0), (0,10) and (0,-10) could at some time become (-10,0), (-30,0), (-20,10), and (-20,-10), but with x.c'=x.c, the circle center would be at (0,0) still! The circle is here but its center is way, way over there! Indeed, although a change of coordinate systems is not movement of any object described in the coordinates, the x.c'=x.c crackpottery is tantamount to the circle staying put but the center moving away. Or vice versa. User Contributions:Top Document: Invariant Galilean Transformations On All Laws Previous Document: 8. What does sci.math have to say about x0'=x0-vt? Next Document: 10. But Isn't (x'-x.c')=(x-x.c) Actually Two Transformations? Single Page [ Usenet FAQs | Web FAQs | Documents | RFC Index ] Send corrections/additions to the FAQ Maintainer: Thnktank@concentric.net (Eleaticus)
Last Update March 27 2014 @ 02:12 PM
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