Top Document: Invariant Galilean Transformations On All Laws Previous Document: 11. But Doesn't (x'-x.c+vt) Prove The Transformation Time Dependent? Next Document: 13. But Isn't (x'-x.c')=(x-x.c) Almost the Definition of a Linear Transform? See reader questions & answers on this topic! - Help others by sharing your knowledge My dictionary relates 'tautology' to needless repetition. That's another form of the x.c' <> x.c-vt idiocy. The repetition involved is the vt transformation term. Apply the -vt term to the x term, and it is needless repetition to apply it anywhere again? The 'again' is to the x.c term. The x.c' = x.c crackpot idiocy. The repetition of the vt terms is required by the presence of two x values to be transformed. Be sure to note the next section. User Contributions:Top Document: Invariant Galilean Transformations On All Laws Previous Document: 11. But Doesn't (x'-x.c+vt) Prove The Transformation Time Dependent? Next Document: 13. But Isn't (x'-x.c')=(x-x.c) Almost the Definition of a Linear Transform? Single Page [ Usenet FAQs | Web FAQs | Documents | RFC Index ] Send corrections/additions to the FAQ Maintainer: Thnktank@concentric.net (Eleaticus)
Last Update March 27 2014 @ 02:12 PM
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